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Circle segment area calculator

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What is a circle segment?

A circular segment is the region of a disc bounded by a chord and the arc the chord cuts off. Picture a full pie slice (a sector), then remove the triangular wedge that connects the two endpoints of the arc to the center — what is left is the segment. It is the curved “cap” sitting between the chord and the arc.

The segment depends on two numbers: the radius rr of the circle and the central angle θ\theta subtended by the chord at the center. The angle can be given in degrees, radians, or gradians; this calculator converts internally.

Key concepts

  • Radius (r) — the distance from the center of the circle to a point on its boundary.
  • Central angle (θ) — the angle formed at the center by the two radii drawn to the endpoints of the chord.
  • Chord — the straight line connecting the two endpoints of the arc.
  • Arc — the curved boundary of the segment, opposite to the chord.
  • Sector — the pie-slice region bounded by the arc and the two radii.
  • Triangle — the isosceles triangle with two sides equal to rr and the included angle θ\theta.

How does the calculator work?

The segment is what is left when the triangle is removed from the sector:

Asegment=AsectorAtriangleA_{\text{segment}} = A_{\text{sector}} - A_{\text{triangle}}

With θ\theta in radians, the sector area is 12r2θ\frac{1}{2} r^2 \theta and the area of the isosceles triangle formed by the two radii is 12r2sinθ\frac{1}{2} r^2 \sin\theta. Subtracting one from the other gives the standard formula.

Formula

If θ\theta is in radians:

A=r22(θsinθ)A = \frac{r^2}{2} \bigl(\theta - \sin\theta\bigr)

If θ\theta is given in degrees, it is first converted to radians with θrad=θdegπ180\theta_{\text{rad}} = \theta_{\text{deg}} \cdot \frac{\pi}{180} before being substituted into the formula.

Worked examples

Example 1: small segment, 60°

A circle has a radius of 10 cm. The chord cuts off a central angle of 60°.

Convert: θrad=60°π180=π31.0472\theta_{\text{rad}} = 60° \cdot \frac{\pi}{180} = \frac{\pi}{3} \approx 1.0472.

A=1022(π3sin60°)=50(1.04720.8660)9.0586 cm2A = \frac{10^2}{2} \left( \frac{\pi}{3} - \sin 60° \right) = 50 \cdot (1.0472 - 0.8660) \approx 9.0586 \text{ cm}^2

Example 2: semicircle, π radians

For a radius of 5 cm and a central angle of π\pi radians (180°), the chord is a diameter and the segment is exactly half the disc:

A=522(πsinπ)=252π39.270 cm2A = \frac{5^2}{2} \bigl(\pi - \sin\pi\bigr) = \frac{25}{2} \cdot \pi \approx 39.270 \text{ cm}^2

Example 3: quarter-circle minus triangle, 90°

For a radius of 10 cm and a central angle of 90°:

A=1022(π2sin90°)=50(π21)28.5398 cm2A = \frac{10^2}{2} \left( \frac{\pi}{2} - \sin 90° \right) = 50 \cdot \left( \frac{\pi}{2} - 1 \right) \approx 28.5398 \text{ cm}^2

This matches the intuition: the quarter sector has area 25π78.5425\pi \approx 78.54 cm², the right triangle has area 5050 cm², and the difference is the segment.

Practical uses

  • Engineering — computing cross-sectional areas of partially filled circular tanks or pipes for fluid flow problems (this is the same calculation used by the circle area calculator when only a portion is filled).
  • Construction and architecture — sizing windows, arches, and recessed details where the curved cap of a circle is a design element.
  • Manufacturing — quoting material for stamped, cut, or machined parts shaped like a circular cap.
  • Civil engineering — estimating earthwork volumes for circular channel cross-sections that are not full.
  • Geometry and trigonometry — verifying the relationship to the circle sector area calculator and the chord length calculator.

Notes

  • The angle must be positive. A 0° angle gives a degenerate segment with zero area.
  • For θ=2π\theta = 2\pi (360°), the formula returns the area of the full circle.
  • The “minor” segment corresponds to angles below 180°. For angles above 180°, the formula gives the larger “major” segment that includes the center.
  • The radius and the area units must be consistent: a radius in metres produces an area in square metres. The unit selector reconverts the result automatically.
  • The result is exact up to the precision of π\pi and the sine function; rounding errors are negligible for everyday use.

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